NEET · 18 September 2026
Which set has zero dipole moment?
Which of the following set of molecules will have zero dipole moment?
A. Ammonia, beryllium difluoride, water, 1,4-dichlorobenzene
B. Boron trifluoride, hydrogen fluoride, carbon dioxide, 1,3-dichlorobenzene
C. Nitrogen trifluoride, beryllium difluoride, water, 1,3-dichlorobenzene
D. Boron trifluoride, beryllium difluoride, carbon dioxide, 1,4-dichlorobenzene
Choose A–D and explain your reasoning.
Reveal answer and corrected explanation
Correct answer: D.
The question concerns the permanent dipole moment of each individual molecule in its usual molecular geometry. Add the dipole contributions as vectors; polar bonds do not necessarily make the whole molecule polar.
In D, BF₃ is trigonal planar: three equivalent B–F bond dipoles at 120° cancel. An isolated BeF₂ molecule is linear, so its two equal, opposite bond dipoles cancel. CO₂ is also linear with equal, opposite bond dipoles. In 1,4-dichlorobenzene (para), the two identical chlorine substituents occupy opposite positions; the molecular symmetry gives zero net dipole moment.
A is incorrect because NH₃ is trigonal pyramidal and polar, and H₂O is bent and polar. B is incorrect because HF is polar and the dipole contributions in 1,3-dichlorobenzene (meta) do not cancel. C contains polar NF₃, H₂O and 1,3-dichlorobenzene.
NF₃ is trigonal pyramidal, not trigonal planar like BF₃. In NCERT's description, its lone-pair contribution opposes the resultant of the N–F bond dipoles, leaving a small nonzero dipole moment; these contributions do not reinforce each other. A lone pair alone is not a universal test of molecular polarity.
Clarification: the original app explanation's BF₃/NF₃ shape comparison and “reinforcing” wording were misleading. The answer remains D; this clarification corrects that wording.
This separate clarification does not mean the original app explanation has been updated.
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